[Solved]Texture 3D Rotation from GUI

I know GUIUtility.RotateAroundPivot. that rotate the GUI around a point.

I want to make 3D rotations. I managed to make 3D rotations with the following code:

Code (CSharp):

1. using UnityEngine;
2. using System.Collections;
3.  
4. public class script : MonoBehaviour {
5.    
6.     public Texture2D texture;
7.     public Vector2 center = new Vector2(100f,100f);
8.     public Vector3 angle = Vector3.zero;
9.     public Vector2 pivot = new Vector2(0.5f,0.5f);
10.    
11.     Texture2D rTexture;
12.     Rect rect = new Rect ();
13.    
14.     void Update(){
15.        
16.         this.rTexture = rotateTexture(this.texture,this.angle,this.pivot);
17.         rect.size = new Vector2(rTexture.width,rTexture.height);
18.         rect.position = center - rect.size * 0.5f;
19.        
20.     }
21.    
22.     void OnGUI(){ GUI.DrawTexture(rect,rTexture,ScaleMode.StretchToFill); }
23.    
24.     Texture2D rotateTexture(Texture2D texture, float angle){ return rotateTexture(texture,new Vector3(0f,0f,angle),new Vector2(0.5f,0.5f)); }
25.     Texture2D rotateTexture(Texture2D texture, Vector3 angle, Vector2 pivot){
26.        
27.         Quaternion Angle    = Quaternion.Euler(angle);
28.         Vector2 e1 = Angle * new Vector2( texture.width,texture.height);
29.         Vector2 e2 = Angle * new Vector2(-texture.width,texture.height);
30.         Texture2D tex = new Texture2D((int)(Mathf.Max(Mathf.Abs(e1.x),Mathf.Abs(e2.x))),
31.                                       (int)(Mathf.Max(Mathf.Abs(e1.y),Mathf.Abs(e2.y))),TextureFormat.RGBA32,false);
32.         Color32[] pixelsTexture = texture.GetPixels32();
33.         Color32[] pixelsTex     = tex.GetPixels32();
34.         for(int w=0;w<pixelsTex.Length;w++) pixelsTex[w].a=0;
35.  
36.         Vector2 position;
37.         int x,y;
38.         float xPivotTex = Mathf.Clamp01(pivot.x)*tex.width;
39.         float yPivotTex = tex.height*(1f-Mathf.Clamp01(pivot.y));
40.         float xPivotTexture = Mathf.Clamp01(pivot.x)*texture.width;
41.         float yPivotTexture = texture.height*(1f-Mathf.Clamp01(pivot.y));
42.         int width  = tex.width-1;
43.         int height = tex.height-1;
44.        
45.         for(int i=0;i<pixelsTexture.Length;i++){
46.            
47.             position = Angle * new Vector2(i%texture.width-xPivotTexture , i/texture.width-yPivotTexture);
48.             x = (int)(position.x + xPivotTex);
49.             y = (int)(position.y + yPivotTex);          
50.             if(!(x < 0 || x > width || y < 0 || y > height)) pixelsTex[x + y * tex.width] = pixelsTexture[i];
51.  
52.         }
53.        
54.         tex.SetPixels32(pixelsTex);
55.         tex.Apply();
56.         return tex;
57.        
58.     }
59.    
60. }

The above code rotates pixels of the original image and draw in the new texture that takes the size needed.

Problem: With this system to increase the size of the new texture pixels are not drawn.

I tried to reverse the process, ie, compute the reverse rotation and reverse rotate the pixels of the new texture to detect which is the closest to the original texture pixel:

Code (CSharp):

1. using UnityEngine;
2. using System.Collections;
3.  
4. public class Texture2DRotation3D : MonoBehaviour {
5.  
6.     public Texture2D texture;
7.     public Vector2 center = new Vector2(100f,100f);
8.     public Vector3 angle = Vector3.zero;
9.     public Vector2 pivot = new Vector2(0.5f,0.5f);
10.  
11.     Texture2D rTexture;
12.     Rect rect = new Rect ();
13.  
14.     void Update(){
15.  
16.         this.rTexture = rotateTexture(this.texture,this.angle,this.pivot);
17.         rect.size = new Vector2(rTexture.width,rTexture.height);
18.         rect.position = center - rect.size * 0.5f;
19.  
20.     }
21.  
22.     void OnGUI(){ GUI.DrawTexture(rect,rTexture,ScaleMode.StretchToFill); }
23.  
24.     Texture2D rotateTexture(Texture2D texture, float angle){ return rotateTexture(texture,new Vector3(0f,0f,angle),new Vector2(0.5f,0.5f)); }
25.     Texture2D rotateTexture(Texture2D texture, Vector3 angle, Vector2 pivot){
26.  
27.         Quaternion Angle    = Quaternion.Euler(Mathf.Repeat(angle.x,89f),Mathf.Repeat(angle.y,89f),Mathf.Repeat(angle.z,360f));
28.         Quaternion invAngle = Quaternion.Inverse(Angle);
29.         Vector2 e1 = Angle * new Vector2( texture.width,texture.height);
30.         Vector2 e2 = Angle * new Vector2(-texture.width,texture.height);
31.         Texture2D tex = new Texture2D((int)(Mathf.Max(Mathf.Abs(e1.x),Mathf.Abs(e2.x))),
32.                                       (int)(Mathf.Max(Mathf.Abs(e1.y),Mathf.Abs(e2.y))),TextureFormat.RGBA32,false);
33.         Color32[] pixelsTexture = texture.GetPixels32();
34.         Color32[] pixelsTex     = tex.GetPixels32();
35.         Vector2 position,invpos;
36.         int x,y;
37.         float xPivotTex = Mathf.Clamp01(pivot.x)*tex.width;
38.         float yPivotTex = tex.height*(1f-Mathf.Clamp01(pivot.y));
39.         float xPivotTexture = Mathf.Clamp01(pivot.x)*texture.width;
40.         float yPivotTexture = texture.height*(1f-Mathf.Clamp01(pivot.y));
41.         int width  = texture.width-1;
42.         int height = texture.height-1;
43.  
44.         for(int i=0;i<pixelsTex.Length;i++){
45.  
46.             position = new Vector2(i%tex.width-xPivotTex , i/tex.width-yPivotTex);
47.             invpos = invAngle * position;
48.            
49.             x = (int)(invpos.x + xPivotTexture);
50.             y = (int)(invpos.y + yPivotTexture);
51.            
52.             if(x < 0 || x > width || y < 0 || y > height) pixelsTex[i].a = 0;
53.             else pixelsTex[i] = pixelsTexture[x+y*texture.width];
54.  
55.         }
56.  
57.         tex.SetPixels32(pixelsTex);
58.         tex.Apply();
59.         return tex;
60.  
61.     }
62.  
63. }

It does not work because to calculate the reverse rotation is necessary to consider the Vector3 value in the Z axis

Does anyone know how to calculate the reverse rotation and the value in the Z axis?

 

Solved using vector equation of the plane: a(x-x0)+b(y-y0)+c(z-z0)=0

At center point 0,0,0, we solve the equation of the z variable: z = (-ax-by)/c

a,b,c is the normal of the plane.

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